How can I display a character above U+FFFF? Say I want to show U+1F384. "\u1F384" is interpreted as "\u1F38" followed by the character "4", and gives the error No glyph found for the ? (\u1F38) character. "\uD83C\uDF84" is interpreted as the character "\uD83C" followed by the character "\uDF84", and gives the error
No glyph found for the ? (\uD83C) character
No glyph found for the ? (\uDF84) character
Here is some example code to demonstrate:
PFont font;
void setup()
{
size(128, 128);
background(0);
font = loadFont("Symbola-8.vlw");
textFont(font, 8);
fill(255);
text("\u1F384", 10, 10);
}
void draw()
{
}
As stated by the tag, this is in the language Processing. \U0001F384 gives the error unexpected char: 'U', presumably because processing doesn't support UTF-32 in that format.
It doesn't really matter how it is displayed, the main problem is making a string contain a character whose decimal codepoint is greater than 65,535.
Unfortunately, there does not appear to be a way to do this.
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