我有两个这样的矩阵
Vehicle1 Year type
Car1 20 A
Car2 21 A
Car8 20 A
第二个
Vehicle2 Year type
Car1 20 M
Car2 21 M
Car7 90 M
我只需要结合基于第一列（车辆）的矩阵，并需要像这样将common标记为A / M
Vehicle Year type
Car1 20 A/M
Car2 21 A/M
Car7 90 M
Car8 20 A
我为此使用了合并功能，但它只打印普通的
您可以加入两个数据框并组合类型列：
dplyr::full_join(df1, df2, by = c('Vehicle1' = 'Vehicle2', 'Year')) %>%
tidyr::unite(type, type.x, type.y, sep = '/', na.rm = TRUE)
# Vehicle1 Year type
#1 Car1 20 A/M
#2 Car2 21 A/M
#3 Car8 20 A
#4 Car7 90 M
数据
df1 <- structure(list(Vehicle1 = c("Car1", "Car2", "Car8"), Year = c(20L,
21L, 20L), type = c("A", "A", "A")), class = "data.frame", row.names = c(NA, -3L))
df2 <- structure(list(Vehicle2 = c("Car1", "Car2", "Car7"), Year = c(20L,
21L, 90L), type = c("M", "M", "M")), class = "data.frame", row.names = c(NA, -3L))
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