I have a file that looks like this: ( Note : A*, B*, C* are placeholders). The file is delimited by ;
AAAA;BBBB;CCCCCCCC;DD;EEEEEEEE;FF;
AAA1;BBBBB;CCCC;DD;EEEEEEEE;FFFFF;
AAA3;BB;CCCC;DDDDDDDDD;EEEEEEE;FF;
I m trying to write a small script that counts the number of occurrences of the delimiter ; and if it is lesser or greater than 5, output said line to a text file.
delim=";"
while read line
do
n_of_occ=$(grep -o "$delim" <<< "$line" | wc -l)
if [[ $n_of_occ < 5 ]] || [[ $n_of_occ > 5 ]]
then
echo $line >> outfile
fi
done
For some reason, this doesn't seem to work and my output is garbled. Could someone assist or provide a different way to tackle this? Perhaps with Perl instead of bash?
Unfortunately every line in your sample data has six semicolons, which means they should all be printed. However, here is a one-line Perl solution
$ perl -ne'print if tr/;// != 5' aaa.csv
AAAA;BBBB;CCCCCCCC;DD;EEEEEEEE;FF;
AAA1;BBBBB;CCCC;DD;EEEEEEEE;FFFFF;
AAA3;BB;CCCC;DDDDDDDDD;EEEEEEE;FF;
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