Pass pointer of array to function that sorts numbers

Taji Published at Dev

Taji

I'm new to C and cannot figure out how to pass a pointer of an array to a function. The function should sort user input numbers in ascending order. I think I've missed something crucial in the function.

I'm able to input the user values but that's as far as I've been able to get without errors.

#include <stdio.h>
int sort(int *p, int i); //function declaration
int main()
{
    int numbers[10]; // ten element array
    int i;

    printf("Please enter ten integer values:\n");
    for(i=0; i<10; i++)
        scanf("%d", (&numbers[i]));

    int *p= &numbers; //a pointer that points to the first element of number
    sort(int *p, int i); //function

}

//function sorts in ascending order
int sort (int *p, int i) //function definition
{
    for (i=0; i<10; i++) //loop through entire array
    {
        printf("%d\n", *p);
    }
    return 0;
}

Vlad from Moscow

You should write

int *p= numbers;//a pointer that points to the first element of number
    sort(p, i); //function

An array passed to a function is converted implicitly to pointer to its first element.

Also the function should look like

//function sorts in ascending order
int sort (int *p, int n) //function definition
{
    for ( int i = 0; i < n; i++) //loop through entire array
    {
        printf("%d\n", *p++);
        // or
        //printf("%d\n", p[i]);
    }

    return 0;
}

Collected from the Internet

Please contact [email protected] to delete if infringement.