C pass pointer as argument in function

Zack Published at Dev

Zack

I came across the following code:

int H3I_hook(int (*progress_fn)(int*), int *id)
{
...
}

I don't understand the purpose of (int*) at the end of the first argument?

sjsam

Demystifying:

int (*progress_fn)(int*)

it can be interpreted like below:

int (*progress_fn)(int*)
 ^       ^          ^
 |       |          |___________ pointer to integer as argument
 |       |
 |     pointer to any function that has V and takes ^
 |
 |__________________________return type an integer

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edited at2021-03-4

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