Suppose I have a function in R that takes multiple arguments, and I'd like to reduce it to a function of fewer arguments by setting some of the arguments to pre-specified values. I'm trying to figure out what is the best way to do this is in R.
For example, suppose I have a function
f <- function(a,b,c,d){a+b+c+d}
I'd like to create or find a function partial that would do the following
partial <- function(f, ...){
#fill in code here
}
new_f <- partial(f, a=1, c= 2)
new_f would be a function of b and d and would return 1+b+2+d
In python I would do
from functools import partial
def f(a,b,c,d):
return a+b+c+d
new_f = partial(f, a=1, c= 2)
I'm actually doing this repeatedly and so I need for this to be as efficient as possible. Can anyone point me to the most efficient way to do this? Right now the best I can do is
partial <- function(f, ...){
z <- list(...)
formals(f) [names(z)] <- z
f
}
Can anyone let me know of a faster way or the best way to do this? This is simply too slow.
There are functions in the pryr package that can handle this, namely partial()
f <- function(a, b, c, d) a + b + c + d
pryr::partial(f, a = 1, c = 2)
# function (...)
# f(a = 1, c = 2, ...)
So you can use it like this -
new_fun <- pryr::partial(f, a = 1, c = 2)
new_fun(b = 2, d = 5)
# [1] 10
## or if you are daring ...
new_fun(2, 5)
# [1] 10
You could also simply change f()'s formal arguments with
f <- function(a, b, c, d) a + b + c + d
formals(f)[c("a", "c")] <- list(1, 2)
f
# function (a = 1, b, c = 2, d)
# a + b + c + d
f(b = 2, d = 5)
# [1] 10
But with the latter, you must name the b and d arguments in f() to avoid an error when you want to leave a and c as their default values.
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