I have a list
n =: i.3
and I want to have an adverb a such that u a n applies u to prefixes of suffixes of n:
<a n
┌─────────────┬───────┬───┐
│┌─┬───┬─────┐│┌─┬───┐│┌─┐│
││0│0 1│0 1 2│││1│1 2│││2││
│└─┴───┴─────┘│└─┴───┘│└─┘│
└─────────────┴───────┴───┘
I've written a sentence that produces desirable result for verb <:
([: <@]\&.> <@]\.) n
┌─────────────┬───────┬───┐
│┌─┬───┬─────┐│┌─┬───┐│┌─┐│
││0│0 1│0 1 2│││1│1 2│││2││
│└─┴───┴─────┘│└─┴───┘│└─┘│
└─────────────┴───────┴───┘
but I cannot get how to make an adverb to use it with any verb.
I see another approach to this problem:
a =: \\.
<a n
┌─┬───┬─────┐
│0│0 1│0 1 2│
├─┼───┼─────┤
│1│1 2│ │
├─┼───┼─────┤
│2│ │ │
└─┴───┴─────┘
([: < (a: ~: ]) # ])"1(<a n)
┌─────────────┬───────┬───┐
│┌─┬───┬─────┐│┌─┬───┐│┌─┐│
││0│0 1│0 1 2│││1│1 2│││2││
│└─┴───┴─────┘│└─┴───┘│└─┘│
└─────────────┴───────┴───┘
but it is also written specifically for <, and maybe not efficient. And I still cannot get how to make an adverb.
It will be even better if I can get the following result:
<a n
┌─┬───┬─────┬─┬───┬─┐
│0│0 1│0 1 2│1│1 2│2│
└─┴───┴─────┴─┴───┴─┘
For example:
(10&#.)a n
0 1 12 1 12 2
Help me please. Thanks in advance.
There is (almost) already an adverb for this. It's the Spread (S:) which you want to apply to level 0.
E.g.
<\ each <\. n
┌─────────────┬───────┬───┐
│┌─┬───┬─────┐│┌─┬───┐│┌─┐│
││0│0 1│0 1 2│││1│1 2│││2││
│└─┴───┴─────┘│└─┴───┘│└─┘│
└─────────────┴───────┴───┘
< S:0 <\ each <\. n
┌─┬───┬─────┬─┬───┬─┐
│0│0 1│0 1 2│1│1 2│2│
└─┴───┴─────┴─┴───┴─┘
+/ S:0 <\ each <\. n
0 1 3 1 3 2
(10&#.) S:0 <\ each <\. n
0 1 12 1 12 2
In other words, your a could be like this:
a =: 1 :'u S: 0 ([: <\&.><\.) y'
(edit) or, as @Tikkanz says in the comments below, you can avoid S: and use the more efficient:
a=: 1 : ';@([: u\&.> <@]\.)'
or
a=: 1 : ';@(<@(u\)\.)'
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