In a batch file, I'm opening a window with a specific name like this:
@echo off
start "my log" /D \logs\ /I powershell -nologo -noexit -command "$host.ui.RawUI.WindowTitle = 'My log'"; get-content logfile.log -wait
So the window title is "My log".
How do you run this command only if the window is not already open. Is there a bat file command to test for this? I'd rather not use a program or a powershell command, just a simple bat file cmd if possible.
Something like this:
@echo off
if EXISTS window("My log") goto skip
start "my log" /D \logs\ /I powershell -nologo -noexit -command "$host.ui.RawUI.WindowTitle = 'My log'"; get-content logfile.log -wait
:skip
@For /f "Delims=:" %A in ('tasklist /v /fi "WINDOWTITLE eq New Folder"') do @if %A==INFO echo Prog not running
More info on batch. Also see for /?.
& seperates commands on a line.
&& executes this command only if previous command's errorlevel is 0.
|| (not used above) executes this command only if previous command's errorlevel is NOT 0
> output to a file
>> append output to a file
< input from a file
| output of one command into the input of another command
^ escapes any of the above, including itself, if needed to be passed to a program
" parameters with spaces must be enclosed in quotes
+ used with copy to concatinate files. E.G. copy file1+file2 newfile
, used with copy to indicate missing parameters. This updates the files modified date. E.G. copy /b file1,,
%variablename% a inbuilt or user set environmental variable
!variablename! a user set environmental variable expanded at execution time, turned with SelLocal EnableDelayedExpansion command
%<number> (%1) the nth command line parameter passed to a batch file. %0 is the batchfile's name.
%* (%*) the entire command line.
%<a letter> or %%<a letter> (%A or %%A) the variable in a for loop. Single % sign at command prompt and double % sign in a batch file.
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