I'm following a tutorial on using Ajax with JavaScript, and this was the code we're making:
$('document').ready(function(){
$.ajax({
url: "AwesomeText.html",
type: "GET",
datatype: "Html"
})
.done(Success)
});
function Success(result){
$("p").append(result);
}
I got how it worked but there is one thing that confused me. We made a Success function to append the requested HTML file to the paragraph in the page, and then we passed a parameter called result, so from what I understand I can name the parameter anything and pass it as an argument and it will work. I took out success and passed in x as an argument and it still worked..
so my question is how does JQuery know it should store the requested HTML document in this parameter we're creating in this function? what if I have other functions will Jquery store the requested file to every function in it's parameter? I don't get how JQuery knows.
Also, there is a .done function in there, is that the same function that's explained here: https://api.jquery.com/deferred.done/ why is it called deferred?
url to ajax it basically fetches that url and returns whatever it got at that url, AwesomeText.html in your case and then it sends the content of that url to success function as a first parametersuccess = Type: Function( Anything data, String textStatus, jqXHR jqXHR )
.done(fn) method makes calling some method after the method on which .done was called [You can say Promise ] which makes synchronous callsYou can check following question for understanding the promises and .done() method
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