I am working through some older code that must return an std::auto_ptr, with which I have relatively little experience. I have run into a situation like this:
// I need to populate this function
std::auto_ptr<Base> Func()
{
std::auto_ptr<Derived> derivedPtr = new Derived;
// now I want to return
return derivedPtr; // error: conversion from std::auto_ptr<Derived> to std::auto_ptr<Base> is ambiguous
}
Do I need to release auto_ptr first? The really overly explicit way would be something like return static_cast<Base>(derivedPtr.release()) but I suspect this isn't necessary.
You can use...
return std::auto_ptr<Base>(derivedPtr); // explicitly use constructor
...or...
return derivedPtr.operator std::auto_ptr<Base>(); // use cast/conversion operator
(The reason you can't just return derivedPtr is that the above are ambiguous candidates).
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