我是一名基本的python程序员,因此希望我的问题的答案会很容易。我正在尝试拿字典并将其附加到列表中。然后,字典更改值,然后再次循环添加。似乎每次执行此操作时,列表中的所有词典都会更改其值以匹配刚刚添加的值。例如:
>>> dict = {}
>>> list = []
>>> for x in range(0,100):
... dict[1] = x
... list.append(dict)
...
>>> print list
我认为结果是,[{1:1}, {1:2}, {1:3}... {1:98}, {1:99}]
但是我得到了:
[{1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}, {1: 99}]
任何帮助是极大的赞赏。
您需要追加一个副本,否则您将一遍又一遍地添加对同一词典的引用:
yourlist.append(yourdict.copy())
我用yourdict
和yourlist
代替dict
and list
; 您不想掩盖内置类型。
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我来说两句