考虑以下参数：
char words[8] = "one two";
string word1;
string word2;
stringstream ss;
此代码的输出：
ss << strtok(words, " ");
ss >> word1;
ss << strtok(NULL, " ");
ss >> word2;
cout << "Words: " << word1 << " " << word2 << endl;
是：
Words: one
而这段代码
ss << strtok(words, " ");
ss >> word1;
char* temp = strtok(NULL, " ");
word2 = temp;
cout << "Words: " << word1 << " " << word2 << endl;
输出为：
Words: one two
为什么stringstream可以处理第一个的返回值，strtok但不能处理第二个？
您应该插入语句
ss.clear();
清除流的eof状态。例如
char words[8] = "one two";
std::string word1;
std::string word2;
std::stringstream ss;
ss << std::strtok(words, " ");
ss >> word1;
ss.clear();
ss << std::strtok(NULL, " ");
ss >> word2;
std::cout << "Words: " << word1 << " " << word2 << std::endl;
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句