因此,假设我具有以下数据框(df1):
Site 1 Site 2 Site 3 Site 4 Site 5 Site 6
Date
2000-01-01 13.0 28.0 76.0 45 90.0 58.0
2001-01-01 77.0 75.0 57.0 3 41.0 24.0
2002-01-01 50.0 29.0 2.0 65 48.0 21.0
2003-01-01 7.0 48.0 14.0 63 12.0 66.0
2004-01-01 11.0 90.0 11.0 5 47.0 6.0
2005-01-01 50.0 4.0 31.0 1 40.0 79.0
2006-01-01 30.0 98.0 91.0 96 43.0 39.0
2007-01-01 50.0 20.0 54.0 65 NaN 47.0
2008-01-01 24.0 84.0 52.0 84 NaN 81.0
2009-01-01 56.0 61.0 57.0 25 NaN 36.0
2010-01-01 87.0 45.0 68.0 65 NaN 71.0
2011-01-01 22.0 50.0 92.0 91 NaN 48.0
2012-01-01 12.0 44.0 79.0 77 NaN 25.0
2013-01-01 1.0 22.0 34.0 57 NaN 25.0
2014-01-01 94.0 NaN 86.0 97 NaN 91.0
2015-01-01 2.0 NaN 98.0 44 NaN 79.0
2016-01-01 81.0 NaN 35.0 87 NaN 32.0
2017-01-01 59.0 NaN 95.0 32 NaN 58.0
2018-01-01 NaN NaN 3.0 14 NaN NaN
2019-01-01 NaN NaN 48.0 9 NaN NaN
2020-01-01 NaN NaN NaN 49 NaN NaN
现在,我可以使用“ first_valid_index()”来查找每列的最后一个有效索引:
lvi = df.apply(lambda series: series.last_valid_index())
产生:
Site 1 2017-01-01
Site 2 2013-01-01
Site 3 2019-01-01
Site 4 2020-01-01
Site 5 2006-01-01
Site 6 2017-01-01
我如何将其应用于另一个数据框,在此我使用此索引来切片另一个数据框的时间序列。可以使用以下内容创建数据框的另一个示例:
import pandas as pd
import numpy as np
from numpy import random
random.seed(30)
df2 = pd.DataFrame({
"Site 1": np.random.rand(21),
"Site 2": np.random.rand(21),
"Site 3": np.random.rand(21),
"Site 4": np.random.rand(21),
"Site 5": np.random.rand(21),
"Site 6": np.random.rand(21)})
idx = pd.date_range(start='2000-01-01', end='2020-01-01',freq ='AS')
df2 = df2.set_index(idx)
如何使用“ lvi”变量索引到df2?
要手动执行此操作,我可以使用:
df_s1 = df['Site 1'].loc['2000-01-01':'2017-01-01']
得到类似的东西:
2000-01-01 13.0
2001-01-01 77.0
2002-01-01 50.0
2003-01-01 7.0
2004-01-01 11.0
2005-01-01 50.0
2006-01-01 30.0
2007-01-01 50.0
2008-01-01 24.0
2009-01-01 56.0
2010-01-01 87.0
2011-01-01 22.0
2012-01-01 12.0
2013-01-01 1.0
2014-01-01 94.0
2015-01-01 2.0
2016-01-01 81.0
2017-01-01 59.0
有没有更好的方法来解决这个问题?此外,每一列是否必须实质上是其自己的数据框才能起作用?任何帮助是极大的赞赏!
好吧,所以在考虑了一段时间之后,尝试提出一个涉及for循环等的详细过程,我得出的结论是,这个简单的数学运算可以解决问题。基本上,我利用了熊猫数据框之间的数学运算方法。
output = df1*0 + df2
这给出了df2的输出,该输出将采用df1的NaN值,如下所示:
Site 1 Site 2 Site 3 Site 4 Site 5 Site 6
Date
2000-01-01 0.690597 0.443933 0.787931 0.659639 0.363606 0.922373
2001-01-01 0.388669 0.577734 0.450225 0.021592 0.554249 0.305546
2002-01-01 0.578212 0.927848 0.361426 0.840541 0.626881 0.545491
2003-01-01 0.431668 0.128282 0.893351 0.783488 0.122182 0.666194
2004-01-01 0.151491 0.928584 0.834474 0.945401 0.590830 0.802648
2005-01-01 0.113477 0.398326 0.649955 0.202538 0.485927 0.127925
2006-01-01 0.521906 0.458672 0.923632 0.948696 0.638754 0.552753
2007-01-01 0.266599 0.839047 0.099069 0.000928 NaN 0.018146
2008-01-01 0.819810 0.809779 0.706223 0.247780 NaN 0.759691
2009-01-01 0.441574 0.020291 0.702551 0.468862 NaN 0.341191
2010-01-01 0.277030 0.130573 0.906697 0.589474 NaN 0.819986
2011-01-01 0.795344 0.103121 0.846405 0.589916 NaN 0.564411
2012-01-01 0.697255 0.599767 0.206482 0.718980 NaN 0.731366
2013-01-01 0.891771 0.001944 0.703132 0.751986 NaN 0.845933
2014-01-01 0.672579 NaN 0.466981 0.466770 NaN 0.618069
2015-01-01 0.767219 NaN 0.702156 0.370905 NaN 0.481971
2016-01-01 0.315264 NaN 0.793531 0.754920 NaN 0.091432
2017-01-01 0.431651 NaN 0.974520 0.708074 NaN 0.870077
2018-01-01 NaN NaN 0.408743 0.430576 NaN NaN
2019-01-01 NaN NaN 0.751509 0.755521 NaN NaN
2020-01-01 NaN NaN NaN 0.518533 NaN NaN
我基本上是想将NaN值从一个Dataframe压印到另一个。我不敢相信我要这么做有多困难。只要我的数据框大小相同,就可以满足我的需求。
现在,我应该能够从这里开始计算每个最后一个有效数据点的变化百分比。谢谢大家的投入!
只是为了向所有人展示我最终想要完成的任务,这是我在大家的帮助和建议下生成的最终代码!
原始df最初看起来像:
Site 1 Site 2 Site 3 Site 4 Site 5 Site 6
Date
2000-01-01 13.0 28.0 76.0 45 90.0 58.0
2001-01-01 77.0 75.0 57.0 3 41.0 24.0
2002-01-01 50.0 29.0 2.0 65 48.0 21.0
2003-01-01 7.0 48.0 14.0 63 12.0 66.0
2004-01-01 11.0 90.0 11.0 5 47.0 6.0
2005-01-01 50.0 4.0 31.0 1 40.0 79.0
2006-01-01 30.0 98.0 91.0 96 43.0 39.0
2007-01-01 50.0 20.0 54.0 65 NaN 47.0
2008-01-01 24.0 84.0 52.0 84 NaN 81.0
2009-01-01 56.0 61.0 57.0 25 NaN 36.0
2010-01-01 87.0 45.0 68.0 65 NaN 71.0
2011-01-01 22.0 50.0 92.0 91 NaN 48.0
2012-01-01 12.0 44.0 79.0 77 NaN 25.0
2013-01-01 1.0 22.0 34.0 57 NaN 25.0
2014-01-01 94.0 NaN 86.0 97 NaN 91.0
2015-01-01 2.0 NaN 98.0 44 NaN 79.0
2016-01-01 81.0 NaN 35.0 87 NaN 32.0
2017-01-01 59.0 NaN 95.0 32 NaN 58.0
2018-01-01 NaN NaN 3.0 14 NaN NaN
2019-01-01 NaN NaN 48.0 9 NaN NaN
2020-01-01 NaN NaN NaN 49 NaN NaN
然后我想到了第二个完整的数据帧(df2):
df2 = pd.DataFrame({
"Site 1": np.random.rand(21),
"Site 2": np.random.rand(21),
"Site 3": np.random.rand(21),
"Site 4": np.random.rand(21),
"Site 5": np.random.rand(21),
"Site 6": np.random.rand(21)})
idx = pd.date_range(start='2000-01-01', end='2020-01-01',freq ='AS')
df2 = df2.set_index(idx)
现在,我将df2中的nan值替换为df中的nan值:
dfr = df2[df.notna()]
然后我反转数据框:
dfr = dfr[::-1]
valid_first = dfr.apply(lambda col: col.first_valid_index())
valid_last = dfr.apply(lambda col: col.last_valid_index())
现在,我要从上一个有效数据点计算百分比变化,该百分比对于每列都是固定的。就最近(或最后一个有效)数据点而言,这使我从现在到过去的变化百分比。
new = []
for j in dfr:
m = dfr[j].loc[valid_first[j]:valid_last[j]]
pc = m / m.iloc[0]-1
new.append(pc)
final = pd.concat(new,axis=1)
print(final)
这给了我:
Site 1 Site 2 Site 3 Site 4 Site 5 Site 6
2000-01-01 0.270209 -0.728445 -0.636105 0.380330 41.339081 -0.462147
2001-01-01 0.854952 -0.827804 -0.703568 -0.787391 40.588791 -0.884806
2002-01-01 -0.677757 -0.120482 -0.208255 -0.982097 54.348094 -0.483415
2003-01-01 -0.322010 -0.061277 -0.382602 1.025088 5.440808 -0.602661
2004-01-01 1.574451 -0.768251 -0.543260 1.210434 50.494788 -0.859331
2005-01-01 -0.412226 -0.866441 -0.055027 -0.168267 1.346869 -0.385080
2006-01-01 1.280867 -0.640899 0.354513 1.086703 0.000000 0.108504
2007-01-01 1.121585 -0.741675 -0.735990 -0.768578 NaN -0.119436
2008-01-01 -0.210467 -0.376884 -0.575106 -0.779147 NaN 0.055949
2009-01-01 1.864107 -0.966827 0.566590 1.003121 NaN -0.214482
2010-01-01 0.571762 -0.311459 -0.518113 1.036950 NaN -0.513911
2011-01-01 -0.122525 -0.178137 -0.641642 0.197481 NaN 0.033141
2012-01-01 0.403578 -0.829402 0.161753 -0.438578 NaN -0.996595
2013-01-01 0.383481 0.000000 -0.305824 0.602079 NaN -0.057711
2014-01-01 -0.699708 NaN -0.515074 -0.277157 NaN -0.840873
2015-01-01 0.422364 NaN -0.759708 1.230037 NaN -0.663253
2016-01-01 -0.418945 NaN 0.197396 -0.445260 NaN -0.299741
2017-01-01 0.000000 NaN -0.897428 0.669791 NaN 0.000000
2018-01-01 NaN NaN 0.138997 0.486961 NaN NaN
2019-01-01 NaN NaN 0.000000 0.200771 NaN NaN
2020-01-01 NaN NaN NaN 0.000000 NaN NaN
我经常知道这些问题没有上下文,因此这是您的输入所获得的最终输出。再次感谢大家的帮助!
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