Char 'apex' C++

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Alessandro Carughi

I am building a simple program that use dynamic array in C++, the program read a file and after I would find a word and when I find it I change from lower case to upper case. So to find a word I control If after and before there are one space or some punctuation char.

When I control if there is a ' (apex) I have a problem:

s[i+j-1] == '''

This is because the second close the first, and the third open another char.

It run if I use the ascii code: s[i+j-1] == 39.

How can I write this program without using ascii code?

Yu Hao

' needs to be escaped in character literal:

s[i+j-1] == '\''

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에서 수정2021-06-1

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