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perl one liners + match word and delete string after separator

debugcn 에 게시 Dev
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user58412

I work with linux/solaris machines and I need to add some rule in my ksh script:

Please advise how to match the password word in file, and delete the value password after the separator "=" with perl liner command

second it will delete only the first password!

For example

  more file  ( before delete the password )

  Password fkwf324ei23
  Password=fkwf324ei23
  Pass_word=fevme
  Secret_Password=vrev873662j
  Password=fkwf324ei23

.

   more file ( after delete the password )

   Password fkwf324ei23
   Password=
   Pass_word=fevme
   Secret_Password=vrev873662j
   Password=fkwf324ei23
choroba

Just replace Password= at a beginning of a line followed by anything with the string Password=:

perl -i~ -pe 's/^Password=.*/Password=/' file

Update

To only replace the first occurence, add a flag:

perl -i~ -pe '$changed = s/^\s*Password=.*/Password=/ unless $changed;' file

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