Java provides me by <? extends class> a way of filtering the java classes that you can use to build in this case the new HashMap, for example:
I can do that:
Map<String,? extends Serializable> map1 = new HashMap<String,String>();
It is correct, because String implements Serializable, so the compiler let me do that.
But when i try to do it:
Map<String,GenericClass<? extends Serializable>> map2 = new HashMap<String, GenericClass<String>>();
Being the GenericClass as it:
public class GenericClass<T>
{
.
.
.
}
The compiler throw an error saying:
Type mismatch: cannot convert from HashMap<String,GenericClass<String>> to Map<String,GenericClass<? extends Serializable>>
I would like to know, what is happen?
Maybe the compiler cannot detect the extends class being part of a generic type.
You would need to use the following:
Map<String, ? extends GenericClass<? extends Serializable>> map2 =
new HashMap<String, GenericClass<String>>();
Nested wildcards are much different from top-level wildcards - only the latter perform wildcard capture. As a result, HashMap<String, GenericClass<String>> is considered inconvertible to Map<String, GenericClass<? extends Serializable>>, because GenericClass<? extends Serializable> is a concrete type argument (and because generics aren't covariant).
See this post for further information on nested wildcards: Multiple wildcards on a generic methods makes Java compiler (and me!) very confused
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