Python을 사용하여 XML 파일 콘텐츠를 찾고 업데이트하는 방법

귀하의 질문을 올바르게 이해했기를 바랍니다. 그러면 모든 distName="MB-85404/TB-85404/ST-4/[a or b or c]"태그 를 찾아서 태그를 대체 하고 업데이트 할 것 85404입니다 .85409<p name="a">

import re
from bs4 import BeautifulSoup


xml_data = ''' <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>'''

soup = BeautifulSoup('<data>' + xml_data + '</data>', 'xml')

r = re.compile(r'^MB-85404/TB-85404/ST-4/(?:a|b|c)')

for o in soup.find_all('managedObject', distName=r):
    o['distName'] = o['distName'].replace('85404', '85409')
    p = o.find('p', {'name':'a'})
    p.string = 'UPDATED ' + p.string

soup.data.unwrap()
print(soup)

인쇄물:

<?xml version="1.0" encoding="utf-8"?>
 <managedObject class="New" distName="MB-85409/TB-85409/ST-4/a" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="b">enabled</p>
<p name="c">640ms</p>
<p name="d">320ms</p>
<p name="e">640ms</p>
<p name="f">1280ms</p>
<p name="g">6</p>
</managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" operation="open" version="xL20A_1911_002">
<p name="h">320ms</p>
<p name="i">enabled</p>
<p name="j">640ms</p>
<p name="k">320ms</p>
<p name="l">640ms</p>
<p name="a">1280ms</p>
<p name="l">6</p>
</managedObject>
<managedObject class="New" distName="MB-85409/TB-85409/ST-4/c" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="p">enabled</p>
<p name="q">640ms</p>
<p name="r">320ms</p>
<p name="s">640ms</p>
<p name="t">1280ms</p>
<p name="u">6</p>
</managedObject>

편집 : 모든에서 변경하려면 다음 85404을 수행 할 수 있습니다.85409distName=

for o in soup.find_all('managedObject', {'distName': True}):
    o['distName'] = o['distName'].replace('85404', '85409')

EDIT2 : 전체 파일을 바꾸려면 :

with open("C:/files/abcd.xml", "r") as f_in:
    xml_data = f_in.read()

with open("C:/files/output.xml", "w") as f_out:
    f_out.write(xml_data.replace("85409","85904"))