WCF：どのプロパティタイプに対してSetLinkを呼び出す必要がありますか

私は次の解決策に行き着きました。ネイサン・リドリーの質問にヒントを見つけました：

/// <summary>
/// Helper class for analyzing a type.
/// </summary>
public static class TypeAnalyzer
{
    /// <summary>
    /// Calculates if the given type is a "simple" type.
    /// </summary>
    /// <param name="type">Type to be checked for simplicity.</param>
    /// <returns>True, if the type is "simple";false otherwise.</returns>
    /// <remarks>
    ///   The following types are assumed to be simple:
    ///   <list type="*">
    ///     <item>string</item>
    ///     <item>int</item>
    ///     <item>decimal</item>
    ///     <item>float</item>
    ///     <item><see cref="StringComparison"/> (enum type)</item>
    ///     <item>int? (nullable simple types)</item> 
    ///   </list>
    ///   The following types are not simple:
    ///   <list type="*">
    ///     <item>Point (struct)</item>
    ///     <item>Point? (nullable struct)</item>
    ///     <item>StringBuilder (class)</item>
    ///   </list>
    /// </remarks>
    public static bool IsSimple(this Type type)
    {
        if (IsNullableType(type))
            return IsNestedTypeSimple(type);

        return type.IsPrimitive
          || type.IsEnum
          || type.Equals(typeof(string))
          || type.Equals(typeof(decimal))
          || type.Equals(typeof(DateTime))
          || type.Equals(typeof(Guid));
    }

    private static bool IsNestedTypeSimple(Type type)
    {
        var nestedType = Nullable.GetUnderlyingType(type);
        return IsSimple(nestedType);
    }

    private static bool IsNullableType(Type type)
    {
        return Nullable.GetUnderlyingType(type) != null;
    }
}

NUnitで記述されたテストケースは次のとおりです。

[TestFixture]
public class TypeAnalyzerTests
{
    [TestCase(typeof(string), true)]
    [TestCase(typeof(int), true)]
    [TestCase(typeof(decimal), true)]
    [TestCase(typeof(float), true)]
    [TestCase(typeof(StringComparison), true)]
    [TestCase(typeof(int?), true)]
    [TestCase(typeof(decimal?), true)]
    [TestCase(typeof(StringComparison?), true)]
    [TestCase(typeof(object), false)]
    [TestCase(typeof(Point), false)]
    [TestCase(typeof(Point?), false)]
    [TestCase(typeof(StringBuilder), false)]
    [TestCase(typeof(DateTime), true)]
    [TestCase(typeof(Guid), true)]
    [TestCase(typeof(Guid?), true)]
    public void IsSimple_WhenCalledForType_ReturnsExpectedResult(Type type, bool expectedResult)
    {
        var isSimple = TypeAnalyzer.IsSimple(type);

        Assert.That(isSimple, Is.EqualTo(expectedResult));
    }
}

最後に、質問で言及した方法を次のように変更しました。

private bool IsLinkedProperty()
{ 
    return (_propertyInfo != null) && !_propertyInfo.PropertyType.IsSimple();
}