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Command works in terminal but not in bash script

debugcn 投稿 Dev
7
Blair Fonville

If I want to delete everything in the current directory except for "myfile", I can use

rm -r !("myfile")

But if I put this in a script (called cleanup):

#!/bin/bash
rm -r !("myfile")

I get:

pi@raspberrypi:~/tmp $ ./cleanup
./cleanup: line 2: syntax error near unexpected token `('
./cleanup: line 2: `rm -r !("file2")'

If I run

ps -p $$

I can see that my terminal is using bash,

 PID TTY          TIME CMD
1345 pts/3    00:00:02 bash

so I'm unclear on what the problem is.

Notes:

  1. I realize that if the script actually worked, it would delete itself. So, my script really would be something more like: rm -r !("cleanup"|"myfile"), but the error message is the same either way.
  2. As shown by the blockquote, this is on a Raspbian OS (9 - stretch), which is Debian based.
  3. I feel like this question is bound to be a duplicate, but I can't find it. There is a similarly named question, but it is in regards to inheriting variables, and so doesn't address my issue.
Benjamin W.

The !(pattern-list) pattern is an extended glob. Many distros have it enabled for interactive shells, but not for non-interactive ones. You can check that with

$ shopt extglob
extglob         on
$ bash -c 'shopt extglob'
extglob         off

To fix your script, you have to turn it on: add

shopt -s extglob

at the beginning of it.

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