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python regular expression to extract file_name from a given directory path

debugcn 投稿 Dev
3
Ayushman Buragohain

I have some folders like-so:

../dog_breeds/images/Images/n02085620-Chihuahua
../dog_breeds/images/Images/n02085782-Japanese_spaniel
../dog_breeds/images/Images/n02086910-papillon
../dog_breeds/images/Images/n02088466-bloodhound
....
....

I want to extract only these info's(Chihuahua, Japanese_spaniel, papillon, bloodhound) from the paths of the files using Python. Can anybody help me ?

Rakesh

You can use str.split here

Ex:

s = """../dog_breeds/images/Images/n02085620-Chihuahua
../dog_breeds/images/Images/n02085782-Japanese_spaniel
../dog_breeds/images/Images/n02086910-papillon
../dog_breeds/images/Images/n02088466-bloodhound
"""

for p in s.splitlines():
    print(p.split("-")[-1])

If you need regex.

import re

for p in s.splitlines():
    print(re.search(r"\-(\w+)$", p).group(1))

Output:

Chihuahua
Japanese_spaniel
papillon
bloodhound

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