不連続な期間のMINおよびMAX日付を検索YYYYMM00

debugcn 投稿 Dev

ニコラエッセ

次の2つのテーブルがあります。

DimensionTimeは、YYYMM00形式でID順に並べられた毎月を含むテーブルです。
LogPlayerは、プレーヤーと特定の月に関連するいくつかの統計があるテーブルです。

私が取得したいのは次のとおりです。

+--------+--------+----------+----------+
| Player |  Team  |  Start   |   End    |
+--------+--------+----------+----------+
| John   | Red    | 20180100 | 20180300 |
| John   | Red    | 20180600 | 20180700 |
| Luke   | Yellow | 20180100 | 20180100 |
| Luke   | Yellow | 20190100 | 20190100 |
+--------+--------+----------+----------+

ピリオドが不連続であるため、MIN関数とMAX関数を使用できません...どうすれば解決できますか？MIN / MAXをGROUPBYと組み合わせて試してみましたが、何も役に立ちません。Stackoverflowで質問や回答が見つかりませんでした。

SELECT *
    INTO #DimensionTime
    FROM (
        SELECT 1 AS [ID], 20180100 AS [TIMEID]
        UNION ALL
        SELECT 2 AS [ID], 20180200 AS [TIMEID]
        UNION ALL
        SELECT 3 AS [ID], 20180300 AS [TIMEID]
        UNION ALL
        SELECT 4 AS [ID], 20180400 AS [TIMEID]
        UNION ALL
        SELECT 5 AS [ID], 20180500 AS [TIMEID]
        UNION ALL
        SELECT 6 AS [ID], 20180600 AS [TIMEID]
        UNION ALL
        SELECT 7 AS [ID], 20180700 AS [TIMEID]
        UNION ALL
        SELECT 8 AS [ID], 20180800 AS [TIMEID]
        UNION ALL
        SELECT 9 AS [ID], 20180900 AS [TIMEID]
        UNION ALL
        SELECT 10 AS [ID], 20181000 AS [TIMEID]
        UNION ALL
        SELECT 11 AS [ID], 20181100 AS [TIMEID]
        UNION ALL
        SELECT 12 AS [ID], 20181200 AS [TIMEID]
        UNION ALL
        SELECT 13 AS [ID], 20190100 AS [TIMEID]
        UNION ALL
        SELECT 14 AS [ID], 20190200 AS [TIMEID]
        UNION ALL
        SELECT 15 AS [ID], 20190300 AS [TIMEID]
    ) A

SELECT *
INTO #LogPlayer
FROM (
    SELECT 'John' AS [Player], 'Red' AS [Team], 20180100 AS [TIMEID]
    UNION ALL
    SELECT 'John' AS [Player], 'Red' AS [Team], 20180200 AS [TIMEID]
    UNION ALL
    SELECT 'John' AS [Player], 'Red' AS [Team], 20180300 AS [TIMEID]
    UNION ALL
    SELECT 'John' AS [Player], 'Red' AS [Team], 20180600 AS [TIMEID]
    UNION ALL
    SELECT 'John' AS [Player], 'Red' AS [Team], 20180700 AS [TIMEID]
    UNION ALL
    SELECT 'Luke' AS [Player], 'Yellow' AS [Team], 20180100 AS [TIMEID]
    UNION ALL
    SELECT 'Luke' AS [Player], 'Yellow' AS [Team], 20190100 AS [TIMEID]
) B

ゴードン・リノフ

これは一種のギャップと島の問題です。SQL Server 2005のようなサポートされていない古いソフトウェアでも、そのバージョンにはが含まれているため、解決可能row_number()です。

1つのトリックは、時刻IDを真正な日付/時刻に変換することです。もう1つのトリックは、日付/時刻の値から連続する月数を引くことによってグループを定義することです。

select player, team, min(timeid), max(timeid)
from (select lp.*,
             row_number() over (partition by player, team order by timeid) as seqnum,
             cast(cast(timeid + 1 as varchar(255)) as datetime) as yyyymm
      from logplayer lp
     ) lp
group by player, team, dateadd(month, - seqnum, yyyymm)
order by player, team, min(timeid);

これがdb <>フィドルです。

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