I'm having a .bss section in which I have a buffer of 8 bytes inside it. Now, I'm looking for a way to store the number 2 inside the buffer without issuing a system call. Is that possible ?
My attempt which doesn't work:
.section .text
.section .bss
.lcomm SAMPLE_BUFFER, 8
.globl _start
_start:
movl $2,SAMPLE_BUFFER
movl $1, %eax
int $0x80
On execution:
$ as --32 buffer.s -o buffer.o
$ ld -m elf_i386 buffer.o -o buffer
$ ./buffer
fish: “./buffer” terminated by signal SIGSEGV (Address boundary error)
You need to make sure to switch back to the .text section before emitting the machine code for _start. As is, you place _start in .bss which is not executable, crashing your program.
Apart from that, your code seems correct.
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