Struggling for a while passing an array as argument but it's not working anyway. I've tried like below:
#! /bin/bash
function copyFiles{
arr="$1"
for i in "${arr[@]}";
do
echo "$i"
done
}
array=("one" "two" "three")
copyFiles $array
An answer with explanation would be nice.
Edit: Basically, i will eventually call the function from another script file. Plz explain the constraints if possible.
Expanding an array without an index only gives the first element, use
copyFiles "${array[@]}"
instead of
copyFiles $array
Use a she-bang
#!/bin/bash
Use the correct function syntax
Valid variants are
function copyFiles {…}
function copyFiles(){…}
function copyFiles() {…}
instead of
function copyFiles{…}
Use the right syntax to get the array parameter
arr=("$@")
instead of
arr="$1"
Therefore
#!/bin/bash
function copyFiles() {
arr=("$@")
for i in "${arr[@]}";
do
echo "$i"
done
}
array=("one 1" "two 2" "three 3")
copyFiles "${array[@]}"
Output is (my script has the name foo)
$ ./foo
one 1
two 2
three 3
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