I have a pointer to a member function defined within a class, e.g.:
class Example {
void (Example::*foo)();
void foo2();
};
In my main code, I then set foo as:
Example *a;
a->foo = &Example::foo2;
However, when I try to call foo:
a->foo();
I get the following compile time error: "error: expression preceding parentheses of apparent call must have (pointer-to-) function type". I'm assuming I'm getting the syntax wrong somewhere, can someone point it out to me?
to call it you would do: (a->*(a->foo))()
(a->*X)(...) - dereferences a member function pointer - the parens around a->*X are important for precedence.
X = a->foo - in your example.
See ideone here for working example
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