I need to get the string before _, but what I've tried is not working properly. The following is a list of input values stored in $b var:
vendor_code
vendor_name
hotel_name_0
hotel_room_type_0
hotel_in_date_0
...
vendor_code
vendor_name
hotel_name_N
hotel_room_type_N
hotel_in_date_N
This is what I have tried:
$a = [
'vendor_code',
'vendor_name',
'hotel_name_0',
'hotel_room_type_0',
'hotel_in_date_0'
];
foreach ($a as $b) {
echo substr($b, 0, -(strlen(strrchr($b, '_')))), PHP_EOL;
}
The code works almost perfectly, but for those, where you have not the ending _N it fails, because it is removing part of the original string (see the output below).
vendor
vendor
hotel_name
hotel_room_type
hotel_in_date
A valid output should be as follow:
vendor_code
vendor_name
hotel_name
hotel_room_type
hotel_in_date
This means, I need to remove all the content after the last _N.
Can any give me some advice here?
Just remove the ending part _N(if occurs) using preg_replace function:
...
foreach ($a as $word) {
echo preg_replace("/_\d+$/", "", $word). PHP_EOL;
}
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