I have a list of paths and values, something like this:
[
{'Path': 'Item/Info/Name', 'Value': 'Body HD'},
{'Path': 'Item/Genres/Genre', 'Value': 'Action'},
]
And I want to build out the full xml structure, which would be:
<Item>
<Info>
<Name>Body HD</Name>
</Info>
<Genres>
<Genre>Action</Genre>
</Genres>
</Item>
Is there a way to do this with lxml? Or how could I build a function to fill in the inferred paths?
You could do something like:
l = [
{'Path': 'Item/Info/Name', 'Value': 'Body HD'},
{'Path': 'Item/Genres/Genre', 'Value': 'Action'},
]
import lxml.etree as et
root_node = l[0]["Path"].split("/", 1)[0]
tree = et.fromstring("<{}></{}>".format(root_node, root_node))
for dct in l:
nodes = iter(dct["Path"].split("/")[1:])
# catch path like Item/Foo where there is only one child.
nxt_child = child = et.Element(next(nodes))
for node in nodes:
# keep adding nodes
nxt_child = et.Element(node)
child.append(nxt_child)
# set value to last node.
nxt_child.text = dct["Value"]
# append it to the tree.
tree.append(child)
print(et.tostring(tree))
Which would give you:
<Item>
<Info>
<Name>Body HD</Name>
</Info>
<Genres>
<Genre>Action</Genre>
</Genres>
</Item>
You know Item is the root node and the first in every Path, so first create a tree using that node and then just add to the tree as you go.
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