I got an error and I'm not sure what it means:
TypeError at / as_view() takes 1 positional argument but 2 were given
from django.db import models
from django.contrib.auth.models import User
from django.contrib import admin
class Employee(models.Model):
user = models.OneToOneField(User)
full_name = models.CharField(max_length=50)
phone_number = models.CharField(max_length=12)
company = models.CharField(max_length=100)
department = models.CharField(max_length=50)
occupation = models.CharField(max_length=50)
class Meta:
verbose_name_plural = 'employees'
admin.site.register(Employee)
views.py
from django.views.generic import TemplateView
from web_app.models import Employee
class EmployeeTemplateView(TemplateView):
model = Employee.objects.all()
template_name = 'index.html'
context_object_name = 'employee_view'
urls.py
from django.conf.urls import url, include
from web_app import routers
from django.contrib import admin
from . import views
from web_app.views import EmployeeTemplateView
admin.autodiscover()
router = routers.DefaultRouter()
router.register(r'employee', views.EmployeeTemplateView, "Employee")
urlpatterns = ['',
url(r'^$', EmployeeTemplateView.as_view({'emp' : 'employees'})),
]
What am I doing wrong?
Thank you in advance!
as_view doesn't take positional arguments, it takes keyword arguments.
EmployeeTemplateView.as_view(emp='employees')
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