Unresolved overloaded function type when attempting to pass a function as an argument

I receive the following error when attempting to compile a lone C++ testing file under G++ with C++11 in place.

spike/cur_spike.cpp: In function ‘int main()’:
spike/cur_spike.cpp:60:44: error: no matching function for call to ‘callFunctionFromName(<unresolved overloaded function type>, std::__cxx11::string&)’
     callFunctionFromName (outputLine, param);
                                            ^
spike/cur_spike.cpp:49:7: note: candidate: template<class funcT, class ... Args> funcT callFunctionFromName(funcT (*)(Args ...), Args ...)
 funcT callFunctionFromName (funcT func(Args...), Args... args) {
       ^
spike/cur_spike.cpp:49:7: note:   template argument deduction/substitution failed:
spike/cur_spike.cpp:60:44: note:   couldn't deduce template parameter ‘funcT’
     callFunctionFromName (outputLine, param);
                                            ^

Here's the code.

#include <iostream>
#include <string>


template <typename T>
void outputLine (T text) {
    std::cout << text << std::endl;
}

template <typename funcT>
funcT callFunctionFromName (funcT func()) {
    return func ();
}
template <typename funcT, typename... Args>
funcT callFunctionFromName (funcT func(Args...), Args... args) {
    return func (args...);
}

int main () {  
    std::string param = "Testing...";
    callFunctionFromName (outputLine, param);

    return 0;
}

I'm currently building this on a Linux system using G++, this code snippet contains all code related to this issue. I'm particularly intrigued about the fact that the compiler is unable to deduce the template parameter funcT for some reason, even though the outputLine function has a clear return type of void.

Setting a pointer of outputLine using void (*outputLinePtr)(std::string) = outputLine and using the pointer as the argument instead does nothing. Any help would be much appreciated.