Can any body explain why <T extends Job> Typed-safe generics is used here ??
This code was written by one of my project team member who is no more part of the team. This looks like a strange Code for me. I just want to rewrite this and use it in another Code. Without deep Understanding i won't be able to change this.
private <T extends Job> void addNewTask (Class<T> prm_objClassToSchedule, String prm_sJobName, String prm_sTriggerName, String prm_sCronExpression) throws ParseException, SchedulerException {
CronTrigger v_objTrigger;
JobDetail v_objJob;
Scheduler v_objScheduler;
}
As told in other answers T should extend Job, so the method could be clearly written like this:
private <T extends Job> void addNewTask (Class<T extends Job> prm_objClassToSchedule, String prm_sJobName, String prm_sTriggerName, String prm_sCronExpression) throws ParseException, SchedulerException {
CronTrigger v_objTrigger;
JobDetail v_objJob;
Scheduler v_objScheduler;
The java compiler needs at least one mention to the exact type of the same generic type T to be able to compile it, no matter if this mention is in the parameter or in the return type. All the other mentions of T will be interpreted as the same class.
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