Java: Heap space error, Euler project 14

I am trying to solve project Euler problem number 14:

The following iterative sequence is defined for the set of positive integers:

• n → n/2 (n is even)
• n → 3n + 1 (n is odd)

Using the rule above and starting with 13, we generate the following sequence:

13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1

It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1.

Which starting number, under one million, produces the longest chain?

NOTE: Once the chain starts the terms are allowed to go above one million.

This is my approach:

public class Euler14 {

public static void main(String[] args) {
    int temp = 0;
    ArrayList<Integer> numbers = new ArrayList<>();
    ArrayList<Integer> numberOf = new ArrayList<>();
    
    for(int i = 2; i<1000000; i++) {
       
        numbers.add(i);
        temp = i;
        
        while(i!=1) {   
            
            if(i%2==0) {
                i = i/2;
            }
            
            else{
                i = (3*i)+1;
            }                    
            
            numbers.add(i);                
        }
        
            numberOf.add(numbers.size());
            Collections.sort(numberOf);
        
            if(numberOf.size()>1) {
                numberOf.remove(0);
            }
            numbers.clear();
            i = temp;
            
            System.out.println("Starting number " + i + "\n" + 
                               "Size: " + numberOf + "\n");  
    }     
}    
}

However, when running this program I get this error at i = 113282:

Exception in thread "main" java.lang.OutOfMemoryError: Java heap space

What could I do to resolve this error, and how can I improve my code?