I want to change the port in given url.
OLD=http://test:7000/vcc3 NEW=http://test:7777/vcc3
I tried below code code, I am able to change the URL but not able to change the port.
>>> from urlparse import urlparse
>>> aaa = urlparse('http://test:7000/vcc3')
>>> aaa.hostname
test
>>> aaa.port
7000
>>>aaa._replace(netloc=aaa.netloc.replace(aaa.hostname,"newurl")).geturl()
'http://newurl:7000/vcc3'
>>>aaa._replace(netloc=aaa.netloc.replace(aaa.port,"7777")).geturl()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: expected a character buffer object
It's not a particularly good error message. It's complaining because you're passing ParseResult.port
, an int
, to the string's replace
method which expects a str
. Just stringify port
before you pass it in:
aaa._replace(netloc=aaa.netloc.replace(str(aaa.port), "7777"))
I'm astonished that there isn't a simple way to set the port using the urlparse
library. It feels like an oversight. Ideally you'd be able to say something like parseresult._replace(port=7777)
, but alas, that doesn't work.
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