I want to print multiple character using printf
. My approach up to now is this-
#include <stdio.h>
int main()
{
printf("%*c\n", 10, '#');
return 0;
}
But this only prints 9 spaces before the #
.
I want to print it like this-
##########
I am unable to figure out how to do this. Please help me?
You can not use printf
like that to print repetitive characters in Ansi C. I suggest you to use a loop like this -
#include <stdio.h>
int main()
{
int i;
for(i = 0; i < 10; i++) putchar('#');
return 0;
}
Or if you have absolutely no desire to use loops, you can do something like this-
#include <stdio.h>
int main()
{
char out[100];
memset(out, '#', 10);
out[10] = 0;
printf("%s", out);
return 0;
}
By the way, using printf
like this also works-
#include <stdio.h>
int main()
{
printf("%.*s", 10, "############################################");
return 0;
}
Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments