Cropping images with loop in Imagemagick

TheNomadicMonad Published at Dev

TheNomadicMonad

I'm trying to batch crop images in a folder. Whenever I try doing this loop

for image in '/home/donald/Desktop/Im'*.jpg; do 
    convert "$image" -gravity center -crop 95X95% "${image%.jpg}"-modified.jpg
done

I end up with the error:

convert.im6: unable to open image `/home/donald/Desktop/Im*.jpg': No such file or directory @ error/blob.c/OpenBlob/2638.
convert.im6: no images defined `/home/donald/Desktop/Im*-modified.jpg' @ error/convert.c/ConvertImageCommand/3044.

Which is bizarre because there are definitely images in the folder and according the meta-data they are jpg

When I run shopt | grep glob I get this output:

dotglob         off
extglob         on
failglob        off
globstar        off
globasciiranges off
nocaseglob      off
nullglob        off

Here's my version information:

GNU bash, version 4.3.11(1)-release (x86_64-pc-linux-gnu)

Echo $- outputs

himBH

Mark Setchell

The correct syntax is:

#!/bin/bash
shopt -s nullglob
for image in $HOME/Desktop/Im*.jpg; do
   convert "$image" ...
done

Another option may be to use the mogrify command which is part of the ImageMagick suite:

# Create an output directory for cropped images
mkdir cropped
# Crop image and direct output to sub-directory
mogrify -gravity center -crop 95x95% -path cropped  *.jpg

You should definitely not parse the output of ls.

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