I was wondering if there is any smooth way of checking the value of an integer in a range in swift.
I have an integer that can be any number between 0 and 1000
I want to write an if statement for "if the integer is between 300 and 700 - do this and if its any other number - do something else"
I could write:
if integer > 300 {
if integer < 700 {
//do something else1
}
//do something
} else {
// do something else2
}
But I want to minimize the amount of code to write since "do something else1" and "do something else2" are supposed to be the same
It doesn't seem that you can write :
if 300 < integer < 700 {
} else {
}
I tried using
if integer == 300..<700 {
}
but that didn't work either. Anybody got a suggestion?
Did you try this?
if integer > 300 && integer < 700 {
// do something
} else {
// do something else
}
Hope this helps
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