here is the example this is the captured packet data
00000000 00 6e 0b 00 .n..
00000004 4d 5a e8 00 00 00 00 5b 52 45 55 89 e5 81 c3 81 MZ.....[ REU.....
00000014 12 00 00 ff d3 89 c3 57 68 04 00 00 00 50 ff d0 .......W h....P..
00000024 68 f0 b5 a2 56 68 05 00 00 00 50 ff d3 00 00 00 h...Vh.. ..P.....
00000034 00 00 00 00 00 00 00 00 00 00 00 00 e0 00 00 00 ........ ........
00000044 0e 1f ba 0e 00 b4 09 cd 21 b8 01 4c cd 21 54 68 ........ !..L.!Th
00000054 69 73 20 70 72 6f 67 72 61 6d 20 63 61 6e 6e 6f is progr am canno
00000064 74 20 62 65 20 72 75 6e 20 69 6e 20 44 4f 53 20 t be run in DOS
00000074 6d 6f 64 65 2e 0d 0d 0a 24 00 00 00 00 00 00 00 mode.... $.......
and i want only the hex part like this
00 6e 0b 00
4d 5a e8 00 00 00 00 5b 52 45 55 89 e5 81 c3 81
12 00 00 ff d3 89 c3 57 68 04 00 00 00 50 ff d0
I try right click on the packet and select copy -> bytes ->hex stream but the hex data I got doesn't look like the above data at all so How Can I copy hex data of captured packet form wireshark ?
thanks for reading
On the Wireshark "packet list" panel, right click the packet you want and:
1) if you select Copy->Bytes->Hex stream, you'll get the hex digits as one long string without white spaces
39cb08004528053f000000006f1105faac11745dac11740c039......
2) if you select Copy->Bytes->Offset Hex, you'll get the hex digits as displayed on the GUI , including the offset of each line starting byte (frame offset)
0010 05 3f 00 00 00 00 6f 11 05 fa ac 11 74 5d ac 11
0020 74 0c 03 9e 03 9d 05 2b 00 00 07 e0 8f ee 8f 1c
0030 ff 00 00 00 00 00 09 0f 00 58 39 cb 60 00 00 00
0040 11 80 08 00 73 00 02 44 00 00 00 00 03 dd de de
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