Batch - How to wait for process with specific name so start and finish?

I'm creating a launch script to start a game launcher which requires a specific Java version. It currently looks like this:

@ECHO OFF
echo Enabling Java 7...
SET JAVA_HOME=C:\Program Files\Java\jre7
echo Active Java version location: %JAVA_HOME%
echo Starting ATLauncher...
start /wait ATLauncher.exe
echo Launcher started!

It just sets the Java version to Java 7 (changes the JAVA_HOME environment variable to the path to the Java 7 jre) and starts the game launcher (ATLauncher.exe) and waits for it to finish. This does what I want it to, except one thing: The process ATLauncher.exe is just a "starter" which starts a debug console and a Java application, which prompts the user to select something to play, and then starts the selected application.

This brings two problems:
1: All applications started after the ATLauncher.exe process are Java programs, so their process names are just javaw.exe, so it's hard to identify them.
2: The batch file closes when the ATLauncher.exe process stops (which is what I expect), but I want it to run until the last of the launched Java processes has been terminated, and then run some more commands, and then stop.

Here is the "flow" I want to achieve:

1. The script is started.
2. The JAVA_HOME variable is changed.
3. The process ATLauncher.exe starts.
4. The process ATLauncher.exe starts two javaw.exe processes.
5. The process ATLauncher.exe stops.
6. One of the javaw.exe processes starts a 3rd javaw.exe process.
7. The 3rd javaw.exe process stops.
8. The 1st and 2nd javaw.exe eventually stops, or the "flow" begins from step 6 again.
9. The script executes some more commands and stops.

I hope this is clear enough! Just tell me if I have to explain something a bit clearer!

Thanks!