Using linux commands, is there any way to know which file has the given line of code from a given project directory?
All directories are traced recursively for all files in subdirectories as well.
say your project is in php
and is in directory /var/www/projectDir/
and the line to be searched is public function getProjectData(
to know where (in which file lying in which subdirectory ) getProjectData
php function is defined?
use the command
find /var/www/projectDir/ -name '*.php'|xargs grep 'public function getProjectData('
the first portion
find /var/www/projectDir/ -name '*.php'
will search all the files which are having extension php
and within directory /var/www/projectDir
the second portion
xargs grep 'public function getProjectData('
will search all the files found in first portion for public function getProjectData(
.
xargs is used to consider the output of first portion as a standard input for second portion.
The symbol |
named pipe
will pipe the output to second portion
output
/var/www/projectDir/sub/directory/somephpfile.php: public function getProjectData($param1, $param2) {
now you can open the file and search for which line the content is defined using
(ctrl + F for gedit) or ( ctrl + W for nano)
or use any of your favorite editor.
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