Suppose I have a text file with 6 columns as below
a|b|c|d|e|f
I know that somwhere in the file the character 'd' exist, but I want to know the column no for it
I have used the following command
awk 's=index($0,"d"){print "position="s}' filename
but it counts the delimiters too which I dont want....I want the output to be 4 in case of "d"
define "|" as Record Seperator, and use NR variable in awk:
awk -v RS="|" '/^d$/{print NR;}' filename
change ^d$ to whatever you want to match.
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