int arr[10]={1,2,3,4,5,6,7,8,9,10};
printf("%p,%p\n", arr, &arr);
printf("%p,%p\n", arr+1, &arr+1);
return 0;
For this code, GCC compiler return
0xbfe41348,0xbfe41348
0xbfe4134c,0xbfe41370
The first line is clear, no problem. But the second line makes me confused. The first address moves to the next int, so it is 4 bytes after arr, clear. However, for &arr+1 I thought it will point to the end of the whole array arr[10], so it should add 4*10 to the address. Do I misunderstand something?
What you think is right and it is done that way only.
Since &arr => 0xbfe41348 and
0xbfe41348 + 0x28(4*10 in decimal) = 0xbfe41370
I think you got confused due to addition of decimal to a hexadecimal number.
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