I have two functions in different source files:
a.cpp
void A()
{
B();
}
b.cpp
void B()
{
std::cout << "B() called from file: " << ??? << " line: " << ??? << std::endl;
}
How can I get the file name and line number of the call?
In general you can do this automatically by hiding your function behind a macro call which passes allong the __FILE__ and __LINE__ values
void _B(const char* file, int line) { ... }
#define B() _B(__FILE__, __LINE__)
This is by no means a foolproof solution though. It's possible for developers to call _B directly or for _B to be called from generated code, assembly, etc .... where there may be no meaningful file / line number
OP asked for an example with arguments
void _C(int p1, char p2, const char* file, int line) { ... }
#define C(p1, p2) _C(p1, p2, __FILE__, __LINE__)
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