I am quite new to developing apps. Still I would have thought that this is a basic action, so if there is already a solved thread I would be OK with the link. But since I am searching for over 2 hours for this I am asking anyway:
I want to dynamically add an element to my layout every time the user clicks a button.
By now I have this:
XML (R.layout.game.xml)
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical">
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/submit_choice"
android:onClick="submitChoice"/>
</LinearLayout>
Java
public void submitChoice(View view)
{
TextView textView = new TextView(this);
textView.setTextSize(40);
textView.setText("text");
LinearLayout ll = new LinearLayout(this);
ll.addView(View.inflate(ll.getContext(), R.layout.game, null));
ll.addView(textView);
setContentView(ll);
}
Since the XML file does not change, it only works once.
So how can I add a second text when the user clicks the button a second time (without changing the XML file)? Examples are appreciated.
The problem comes from this line, that recreate the whole layout every time:
LinearLayout ll = new LinearLayout(this);
You should define it and setContentView(ll)
outside the submitChoice
function. Then on click only create and add the textView
, then call ll.invalidate();
to see the changes.
Something like:
LinearLayout ll;
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.game);
ll = (LinearLayout) findViewById(R.id.ll_game);
}
// More code...
public void submitChoice(View view) {
TextView textView = new TextView(this);
textView.setTextSize(40);
textView.setText("text");
ll.addView(textView);
ll.invalidate();
}
where ll_game
is the id you have to set in xml for your LinearLayout
.
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