Calling a function when an activity is returned to from fragment

Lewis Smith Published at Java

Lewis Smith :

I have a fragment that I call like so from my activities onCreate

android.app.FragmentManager fragmentManager = getFragmentManager();

DeviceControlFragment newFragment = new DeviceControlFragment();

newFragment.device = device;
fragmentManager.beginTransaction()
        .replace(R.id.content_frame, newFragment)
        .commit();

In the fragment I can either pop the back stack or hit back like so:

getFragmentManager().popBackStack();

getActivity().onBackPressed();

But I need something in the activity so that I know we have returned there, is there something similar to onActivityResult that I can override in the activity to know when the fragment has been 'finished'

Zaid Mirza :

Declare a interface inside fragment and implement it in your activity and send response to activity inside onDetach(),onDestroy or onPaused method of fragment, any of them which suits you. I will prefer onDetach or onDestroy

Here is sample for that:

public class MyFragment extends Fragment {

    @Nullable
    @Override
    public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        return super.onCreateView(inflater, container, savedInstanceState);
    }

    private Test mListener;

    public interface Test{
        void imLeavingYou();
    }

    @Override
    public void onAttach(Context context) {
        super.onAttach(context);
        mListener = (Test) context;
    }

    @Override
    public void onDetach() {
        super.onDetach();
        if(mListener != null){
            mListener.imLeavingYou();
        }
    }
}

And in your Activity do this:

public class MyActivity extends AppCompatActivity implements MyFragment.Test {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my);
    }

    @Override
    public void imLeavingYou() {
        // Okay thanks for informing
    }
}

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