I've been working on Project Euler questions as part of learning how to code in Lasso and am wondering if my solution can be improved upon. Here is what I've got below for question #1 in Lasso 8 code, and it returns the correct answer:
var ('total' = 0);
loop(1000-1);
loop_count % 3 == 0 || loop_count % 5 == 0 ? $total += loop_count;
/loop;
output($total);
My question: is there a better or faster way to code this? Thanks!
Actually Chris it looks like my L9 code answer was almost exactly the same. However what I had to do to time is was wrap it in a loop to time it 1000 times.
Lasso 9 can do Microseconds, whereas versions prior can only time in milliseconds.
Below are 3 ways - the first is yours, then my two versions.
define br => '<br>'
local(start_time = micros)
loop(1000)=>{
var ('total' = 0);
loop(1000-1);
loop_count % 3 == 0 || loop_count % 5 == 0 ? $total += loop_count;
/loop;
$total;
}
'Avg (L8 code in 9): '+(micros - #start_time)/1000+' micros'
br
br
local(start_time = micros)
loop(1000)=>{
local(sum = 0)
loop(999)=>{ loop_count % 3 == 0 || loop_count % 5 == 0 ? #sum += loop_count }
#sum
}
'Avg (incremental improvement): '+(micros - #start_time)/1000+' micros'
br
br
local(start_time = micros)
loop(1000)=>{
local(sum = 0)
loop(999)=>{ not (loop_count % 3) || not(loop_count % 5) ? #sum += loop_count }
#sum
}
'Avg using boolean not: '+(micros - #start_time)/1000+' micros'
The output is:
Avg (L8 code in 9): 637 micros
Avg (incremental improvement): 595 micros
Avg using boolean not: 596 micros
Note that I didn't use "output" as it's redundant in many situations in 8 and completely redundant 9 :)
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