I want to print N lines per second.
for i := 0; i < N; i++ {
fmt.Println(getLogs())
time.Sleep(1000000000/N * time.Nanosecond)
}
But it seems fmt.Println() and getLogs() will also consume time. So actually it will cost me more than 1s to print N lines.
Say getLogs() and fmt.Println() will both cost 1 ms. And I want to print 1 million lines per second. Therefore, to print 1 line will cost 1 ms to getLogs(), 1 ms to print, and 1 ms to sleep... It will cost me 3s to print N lines.
Any better solutions to achieve this more accurately?
You may use time.NewTicker (try The Go Playground):
package main
import (
"fmt"
"time"
)
func main() {
const N = 4
ticker := time.NewTicker(1000000000 / N * time.Nanosecond)
for i := 0; i < N; i++ {
fmt.Println(getLogs(i))
<-ticker.C
}
ticker.Stop()
}
func getLogs(i int) int {
time.Sleep(1 * time.Millisecond)
return i
}
output:
0
1
2
3
See func NewTicker(d Duration) *Ticker Docs:
NewTickerreturns a newTickercontaining a channel that will send the time with a period specified by the duration argument. It adjusts the intervals or drops ticks to make up for slow receivers. The duration d must be greater than zero; if not,NewTickerwill panic. Stop the ticker to release associated resources.
Also see: Running code at noon in Golang
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