I created a method to count a substring 'e' in a string passed as an argument. If there isn't a substring 'e' in the string, it should return "There is no \"e\"." I am trying to achieve this:
'e' is in a string."e", return "There is no "e"."nil, return nil.This is my code:
def find_e(s)
if !s.include?("e")
"There is no \"e\"."
elsif s.empty?
""
else s.nil?
nil
end
s.count("e").to_s
end
find_e("Bnjamin")
It skips the if statement and it still uses the method count. Why is this?
To achieve what you want you could move your string.count to the else statement in your if, because actually you're making your method return the quantity of e passed in the count method over your string, but what happens inside the if isn't being used:
def find_e(s)
if s.nil?
nil
elsif s.empty?
''
elsif !s.include?("e")
"There is no \"e\"."
else
s.count("e").to_s
end
end
p find_e("Bnjamin") # => "There is no \"e\"."
p find_e("Benjamin") # => "1"
p find_e(nil) # => nil
p find_e('') # => ""
And also your validations must be in order, first check nil values, then empty values, and then the rest, if you don't then you'll get some undefined method ___ for nil:NilClass errors.
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