Can anyone explain this code? How value is assigned to only variable m but the output is for all variables change. Also the roles of logical operator and increment operators over here.
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i=-3, j=2, k=0, m;
m = ++i || ++j && ++k;
printf("%d%d%d%d\n", i, j, k, m);
return 0;
}
|| or logical OR operator has a short-circuit property. It only evaluated the RHS is the LHS is FALSY.
In your case, the evaluation of ++x produces a value of -2, which is not FALSY (0). Hence, the RHS is never evaluated.
To break it down:
m = ++i || ++j && ++k;
>> m = (++i) || (++j && ++k);
>> m = (-2) || (++j && ++k);
>> m = 1 // -2 != 0
So, only the value of m and i are changed, remaining variables will retain their values (as they are not evaluated).
That said, the result of the logical OR operator is either 0 or 1, an integer value. The result is stored in m, in your case.
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