I am trying to write a regular expression which I can chain a few not rules together. I need to validate a number string to check that it does NOT match a few rules.
I need it to:
Here is what I'm trying so far:
var re = new RegExp(/^(.)\1{8}$|^000|0000$/);
re.test("111111111"); // true; all same digit
re.test("000112222"); // true; starts with zeroes
re.test("111110000"); // true; ends in zeroes
re.test("123456789"); // false
re.test("111223344"); // false
This works for the first three cases by yielding TRUE, how can I invert the test to have it be false unless it meets the 3 rules?
(I know I can just flip it in the JS with a !, I'm looking for a regex solution)
Putting all rules together, you can use this regex:
/^(?!0{3})(?!.*0{4}$)(\d)(?!\1*$)\d*$/gm
RegEx Breakup:
^ # start
(?!0{3}) # negative lookahead to assert failure when we have 3 0s at start
(?!.*0{4}$) # negative lookahead to assert failure when we have 4 0s at end
(\d) # match a digit and capture in group #1
(?!\1*$) # negative lookahead to assert we don't have same digit until end
\d* # match zero or more digits
$ # end
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