I keep getting this error: syntax error near unexpected token 'done' but I don't understand why.
I tried adding dos2unix *.sh after #!/bin/sh, but that just gave me an error that said no such file or directory in addition to the "done" error.
This is a .sh file. I'm very new to writing scripts. Help?
I'm running
sh thisfile.sh program_input input
on linux
edit I added some quotations around the variables- same error
#!/bin/sh
fst=$1
input=$2
while read line
do
result=$(cat "$line" | program "$fst")
if [ "$result" = "" ];
then
printf "$line\t=>\t *none* 0\n"
else
printf "$line\t=>\tyes\n"
fi
done < "$input"
"$input" is just four rows of words like "they" "can" "fish" "they" "can" "take" "table"
If I run cat "$line" | program "$fst" it works fine
note if I take out everything in the loop and just printf $line it gives the same "done" syntax error
syntax error near unexpected token 'done' is the error Bash gives when it sees the reserved word done without a matching do before it. It has nothing to do with quotes, but most likely a lot to do with your file having DOS/Windows-style CRLF line endings. The carriage return (CR, \r) is seen by the shell as a regular character, so it doesn't see the reserved word do, but do\r instead. On the other hand, on the last line it does recognize done, since it's separated from the line end, and the CR there with that space.
Run the script file itself through dos2unix. Don't add the dos2unix command in the script file.
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