This is not one of those questions for which I dont know a answer but I am trying to find a better more effective way so here I go.
when saving file name in java I am saving it like this
private static final String REPORT_FILE_PREFIX = "ask_ques"; //$NON-NLS-1$
private static final String TXT_EXTENSION = ".txt"; //$NON-NLS-1$
StringBuilder fileName= new StringBuilder();
fileName.append(tempFilePath.toString()).append(REPORT_FILE_PREFIX)
.append(uniqueId.toString()).append(TXT_EXTENSION);
This is going to save the file something like ask_ques_1234.txt all is well and good. Now when opening the file I need to open in based on its extension like notepad for txt, excel so on and so forth.Like I do below
if (FilenameUtils.getExtension(fileName.getName()) == CSV_EXTENSION) {
// Open the .csv file based on the local file type
// association
} else if (FilenameUtils.getExtension(fileName.getName()) == TXT_EXTENSION) {
// open the .txt file based on file type assocaition
}
the problem here is that FilenameUtils.getExtension(reportFile.getName()) returns a value of txt but TXT_EXTENSION has .txt as its value.
Do not want to create static variable for the .. Wanted to see if there is simeple regex or something similar you guys know off to ignore the . when comparing.
Instead of fileName.getName()) == CSV_EXTENSION use fileName.getName()).equals(CSV_EXTENSION).
In Java == stands for reference comparision and String#equals compares char by char.
To compare csv with .csv you can try the following:
CSV_EXTENSION.substring(1).equals(fileName.getName()))
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