I have a variable named $path. I want to pass this variable from PHP to a javascript function.
<button onclick='myFunctionContact(\"" . $row1['id'] . "\")'>
<img border='0' alt='Contacts' src='".$imgpth."peoplesmall.png'>
</button>
<script>
function myFunctionContact(id) {
window.open('!!!$path should go here!!!'+id, '', 'toolbar=no,scrollbars=yes,resizable=yes,top=200,left=500,width=400,height=400');
}
</script>
How do I get the URL in path to display inside of the function, in the desired place?
I tried printing the variable into a javascript variable and then placing that variable into the function, but the popup window no longer works when I do that.
function myFunctionContact(id) {
var test1 = <?php echo $path; ?>;
window.open(test1 +id, '', 'toolbar=no,scrollbars=yes,resizable=yes,top=200,left=500,width=400,height=400');
}
I Know I am doing it wrong, but I have no idea how. Any advice would be greatly appreciated.
I think the problem is how you are echo the path:
Instead of:
var test1 = <?php echo $path; ?>
i think it should be
var test1 = <?php echo '"'.$path.'";'; ?>
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